scala - Pattern match on Tuple2 of Success -

i have 2 futures of try , want if both of them complete. both futures independent. here code

def a1: future[try[string]] = future { success("a1") } def a2: future[try[int]] = future { success(2) }  val r1 = {   c1 <- a1   c2 <- a2 } yield (c1, c2) r1.map {   case tpl: (success[string], success[int]) =>     println("success")   case _ =>     println("failure") } 

this prints success. problem because pattern matching on tuple2, because of erasure if second element failure first case executed. if change a2

def a2: future[try[int]] = future { failure(new internalerror("error")) } 

and again execute this

val r1 = {   c1 <- a1   c2 <- a2 } yield (c1, c2) r1.map {   case tpl: (success[string], success[int]) =>     println("success")   case _ =>     println("failure") } 

now when a2 returns failure above code still prints success. how fix this? non pretty solution check elements of tuple using isinstanceof[success[string]] , isinstanceof[success[int]] , act on truth values there better?

you can pattern match on tuple content:

r1.map {   case (_: success[string], _: success[int]) =>     println("success")   case _ =>     println("failure") } 

this way overcomes type erasure calling tuple's unapply method, getting tuple elements , checking types. , tuple elements have runtime types intact either success or failure.