image - Javascript background changer no working -

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i want implement background image changer in code, doesn't seem work.

here js:

function xax() {     var p = document.getelementbyid("background1");     var o = document.getelementbyid("background2");     var = document.getelementbyid("background3");     if {p.checked === true} {         document.body.style.backgroundimage = "url(gates.jpg)";     }     else if {o.checked === true} {         document.body.style.backgroundimage = "url(city.jpg)";     }     else if {i.checked === true} {         document.body.style.backgroundimage = "url(forest.jpg)";     }     }

here html:

    <input type="radio" id="background1" name="background" >gates of argonath</input><br>     <input type="radio" id="background2" name="background" >minas tirith</input><br>     <input type="radio" id="background3" name="background" >rivendell</input><br>     <input type="button" value="submit" onclick="xax()">

please find correct code below

<html>     <body>     <input type="radio" id="background1" name="background" >gates of argonath</input><br>     <input type="radio" id="background2" name="background" >minas tirith</input><br>     <input type="radio" id="background3" name="background" >rivendell</input><br>     <input type="button" value="submit" onclick="xax()">     <body>     <script>     function xax() {         var p = document.getelementbyid("background1");         var o = document.getelementbyid("background2");         var = document.getelementbyid("background3");         if (p.checked == true) {             document.body.style.backgroundimage = "url(gates.jpg)";         }         else if (o.checked == true) {             document.body.style.backgroundimage = "url(city.jpg)";         }         else if (i.checked == true) {             document.body.style.backgroundimage = "url(forest.jpg)";         }     }     </script> </html>

you using { after if , else if statement, should use (


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