java - Why do I get wrong output? -

i new java , trying write simple code. here description: write program prompts user number x. print numbers 1 x. however, in place of multiples of 4 print “qqqq”. in place of multiples of 7, print “seven”. if number divisible both 4 , 7 print “qqqqseven”. means if input 4, output should 1, 2, 3, (qqqq), ...but 1(qqqq), 2(qqqq), 3(qqqq), 4(qqqq)..... can me , let me know doing wrong? appreciated. you.

public static void main(string args[]) {      //print method     system.out.println("enter number upto want print: ");      scanner input = new scanner(system.in);         int x;         x = input.nextint();       for(int i=1; <= x; i++)     {         system.out.println(i);      //if x multiples of 4     if (x % 4 == 0)             system.out.println("qqqq");     //if x multiples of 7     if (x % 7 == 0)             system.out.println("seven");     //if x divisible 4 , 7     if (x % 4 == 0 && x % 7 == 0)             system.out.println("qqqqseven");      } } 

}

the idea here use if condition specific least specific. in case specific condition divisor of 4 , 7, followed divisor of 4, divisor fo 7 , least specific 1 means else. if arrage if conditions in order you'll result.

note: practice close scanner or resources open. :)

import java.util.scanner;  public class testprogram {      public static void main(string[] args) {         system.out.println("enter number upto want print: ");         scanner input = new scanner(system.in);         int x;         x = input.nextint();          (int = 1; <= x; i++) {             if(i%4 == 0 && i%7 == 0) {                 system.out.println("qqqqseven");             } else if(i%4 == 0) {                 system.out.println("qqqq");             } else if(i%7 == 0){                 system.out.println("seven");             } else {                 system.out.println(i);             }         }         input.close();     } }