c# - How to Let Two Processes Running on Different Hosts Communicate via Named Pipe -

-

i'm using named pipes let 2 processes running on different hosts communicate. here server code:

public class pipeserver {     public static void main()     {         pipesecurity ps = new pipesecurity();         ps.addaccessrule(new pipeaccessrule("everyone",             pipeaccessrights.fullcontrol,             system.security.accesscontrol.accesscontroltype.allow));          namedpipeserverstream pipeserver = new namedpipeserverstream(            "testpipe", pipedirection.inout, 4,            pipetransmissionmode.message, pipeoptions.writethrough,            1024, 1024, ps);          streamreader sr = new streamreader(pipeserver);         streamwriter sw = new streamwriter(pipeserver);          {             try {                 pipeserver.waitforconnection();                 sw.writeline("waiting");                 sw.flush();                 pipeserver.waitforpipedrain();                 string message = sr.readline();                 sw.writeline("got message " + message);             } catch (exception ex) { throw ex; } {                 pipeserver.waitforpipedrain();                 if (pipeserver.isconnected) { pipeserver.disconnect(); }             }         } while (true);     } }

... , here client code:

public class pipeclient {     static void main(string[] args) {         namedpipeclientstream pipeclient = new namedpipeclientstream(             "10.225.154.59", "testpipe",             pipedirection.inout, pipeoptions.none,             tokenimpersonationlevel.none);          if (pipeclient.isconnected != true) { pipeclient.connect(); }          streamreader sr = new streamreader(pipeclient);         streamwriter sw = new streamwriter(pipeclient);          string temp;         temp = sr.readline();          if (temp == "waiting") {             try {                 sw.writeline("hello");                 sw.flush();                 pipeclient.close();             } catch (exception ex) { throw ex; }         }     } }

after start pipeserver on remote host, run client on workstation... following error message:

unhandled exception: system.io.ioexception: logon failure: unknown user name or bad password. @ system.io.__error.winioerror(int32 errorcode, string maybefullpath) @ system.io.pipes.namedpipeclientstream.connect(int32 timeout) @ system.io.pipes.namedpipeclientstream.connect() pipeclient.program.main(string[] args) in g:\my projects\lab\namepipes\program.cs:line 18

the user runs pipeserver on remote host different user runs pipeclient on workstation... should not issue since i've added proper access rule.

am missing something?

edit additional info suggested alexei. user runs server local administrator, while user runs client domain user. there way let send message server?


Comments

Post a Comment

Popular posts from this blog

Java 3D LWJGL collision -

-
i making 3d java game lwjgl library, , wondering how add collision detection, player not go through models. i using obj models. here objloader class, loads models: package renderengine; import java.io.bufferedreader; import java.io.file; import java.io.filenotfoundexception; import java.io.filereader; import java.util.arraylist; import java.util.list; import models.rawmodel; import org.lwjgl.util.vector.vector2f; import org.lwjgl.util.vector.vector3f; public class objloader { public static rawmodel loadobjmodel(string filename, loader loader){ filereader fr = null; try { fr = new filereader(new file("res/"+filename+".obj")); } catch (filenotfoundexception e) { system.err.println("couldn't load file!"); e.printstacktrace(); } bufferedreader reader = new bufferedreader(fr); string line; list<vector3f> vertices = new arraylist<vector3f...
Read more

spring - SubProtocolWebSocketHandler - No handlers -

-
i have ugly error during deploying spring app on jboss. 18:11:16,025 error [org.apache.catalina.core.containerbase.[jboss.web].[default-host].[/consumer]] (msc service thread 1-7) exception sending context initialized event listener instance of class org.springframework.web.context.contextloaderlistener: org.springframework.context.applicationcontextexception: failed start bean 'subprotocolwebsockethandler'; nested exception java.lang.illegalargumentexception: no handlers @ org.springframework.context.support.defaultlifecycleprocessor.dostart(defaultlifecycleprocessor.java:176) [spring-context-4.1.3.release.jar:4.1.3.release] @ org.springframework.context.support.defaultlifecycleprocessor.access$200(defaultlifecycleprocessor.java:51) [spring-context-4.1.3.release.jar:4.1.3.release] @ org.springframework.context.support.defaultlifecycleprocessor$lifecyclegroup.start(defaultlifecycleprocessor.java:346) [spring-context-4.1.3.release.jar:4.1.3.release] @ org.s...
Read more

methods - python can't use function in submodule -

-
my folder structure this: pythonstuff/ program.py modulea/ __init__.py foo.py bar.py here's code bar.py : def hello(): print("hello, world!") here's code program.py : #!/usr/bin/env python3 modulea import bar bar.hello() i run $ python3 program.py somehow error: file "program.py", line 3, in <module> bar.hello() attributeerror: 'module' object has no attribute 'hello' edit: __init__.py file empty. edit2: after trying realized had bar.py in root directory contained hello() method. bar.py in modulea/ directory empty. add it import os __all__ = [] module in os.listdir(os.path.dirname(__file__)): if module != '__init__.py' , module[-3:] == '.py': __all__.append(module[:-3]) the init .py files required make python treat directories containing packages; done prevent directories common name, such string, unintentionally hiding v...
Read more